0=437x^2+103x+11

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Solution for 0=437x^2+103x+11 equation:



0=437x^2+103x+11
We move all terms to the left:
0-(437x^2+103x+11)=0
We add all the numbers together, and all the variables
-(437x^2+103x+11)=0
We get rid of parentheses
-437x^2-103x-11=0
a = -437; b = -103; c = -11;
Δ = b2-4ac
Δ = -1032-4·(-437)·(-11)
Δ = -8619
Delta is less than zero, so there is no solution for the equation

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